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12x^2-288x+1296=0
a = 12; b = -288; c = +1296;
Δ = b2-4ac
Δ = -2882-4·12·1296
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20736}=144$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-288)-144}{2*12}=\frac{144}{24} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-288)+144}{2*12}=\frac{432}{24} =18 $
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